Prove that log3 to the base 2 , is not a rational number.
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Assume log(base 2)3 is rational
This means that log(base 2)3 = a/b where a and b are integers
2^(a/b) = 3
2^a = 3^b
Note that 2^a MUST be even if 'a' is an integer
Note that 3^b MUST be odd if 'b' is an integer
Hence a and b cannot both be integers
Hence a/b is irrational
Hence, using proof by contradiction, log(base 2)3 is irrational
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Assume log(base 2)3 is rational
This means that log(base 2)3 = a/b where a and b are integers
2^(a/b) = 3
2^a = 3^b
Note that 2^a MUST be even if 'a' is an integer
Note that 3^b MUST be odd if 'b' is an integer
Hence a and b cannot both be integers
Hence a/b is irrational
Hence, using proof by contradiction, log(base 2)3 is irrational
...........Be always brainliest........
............ Thanks..........
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