Prove that median of a traingle divides it into 2 traingles of equal areas
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Let ABC be a triangle and Let AD be one of its medians.
In △ABD and △ADC the vertex is common and these bases BD and DC are equal.
Draw AE⊥BC.
Now area(△ABD)=
2
1
×base×altitude of△ADB
=
2
1
×BD×AE
=
2
1
×DC×AE(∵BD=DC)
but DC and AE is the base and altitude of △ACD
=
2
1
× base DC × altitude of △ACD
=area△ACD
⇒area(△ABD)=area(△ACD)
Hence the median of a triangle divides it into two triangles of equal areas.
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