prove that op*oq=r^2
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Heya,
We, can prove this by using the similarity criteria of the triangle.
Proof:
In triangle APO and triangle QAO
Angle OAP = Angle OQA. (each 90°)
Angle AOP = Angle AOQ (Common)
So,
triangle APO ~ triangle QAO
By applying BPT theorem, we get;
AO/QO = PO/AO
=> AO² = PO×QO
By the fig. we can see that AO I'd 'r'
So,
PO×QO = r²
Hence Proved.
Hope this helps...:)
We, can prove this by using the similarity criteria of the triangle.
Proof:
In triangle APO and triangle QAO
Angle OAP = Angle OQA. (each 90°)
Angle AOP = Angle AOQ (Common)
So,
triangle APO ~ triangle QAO
By applying BPT theorem, we get;
AO/QO = PO/AO
=> AO² = PO×QO
By the fig. we can see that AO I'd 'r'
So,
PO×QO = r²
Hence Proved.
Hope this helps...:)
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