prove that p is ll to m
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Given:Four lines AN,AM,BR,AB such that ∠ACB =45°,∠ABC=35°.,∠PDA = 80°
Required to prove:p||m
Proof
In ΔACB
∠A+∠B+∠C = 180°
∠A = 180° - (45° + 35°)
∴∠A =100°
Now ∠DAM and ∠CAB Are vertically opposite angles and are equal..
∴∠DAM = 100°
Here ∠DAM +∠PDA=100+80=180
When two lines are cut by a transversal such that the co-interior angles are supplementary,then the lines are parallel.
Thus p || m
Hence proved
Required to prove:p||m
Proof
In ΔACB
∠A+∠B+∠C = 180°
∠A = 180° - (45° + 35°)
∴∠A =100°
Now ∠DAM and ∠CAB Are vertically opposite angles and are equal..
∴∠DAM = 100°
Here ∠DAM +∠PDA=100+80=180
When two lines are cut by a transversal such that the co-interior angles are supplementary,then the lines are parallel.
Thus p || m
Hence proved
krishna117:
so sweet of u thnk u
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0
yes p is parellal to m because it is ahown in the figure
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