Question

prove that root 3 + 2 is irrational number ​

Answer 1

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Answer 2

Assume

$\sqrt{3} + 2is \: rational$

a, b are Co primes and b is not equal to 0

$\sqrt{3} + 2 = \frac{a}{b}$

$\sqrt{3} = \frac{a - 2b}{b}$

Which is not possible to to have a rational number =to irrational number

Thus,

$\sqrt{3 } + 2 \: is \: irrational$