prove that sec square theta=1+tan square theta
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Answer:
LHS= sec²theta = 1/cos²theta
and
RHS= 1+ tan²theta = 1+ sin²theta / cos²theata =cos²theta + sin²theta/ cos²theta = 1/ cos²theta ( as cos²theata + sin²theta = 1)
LHS = rhs
Answered by
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Answer:
Step-by-step explanation:
sec²A=1+tan²A
1+tan²A = 1+sin²A/cos²A
= (cos²A+sin²A)/cos²A
= 1/cos²A=sec²A
lhs=rhs
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