prove that (sec square theta + tanA)(1-sinA)=cosA
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l hope this helps you
I had use the formula given below:-
sin²theta +cos²theta=1
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sorry i couldn't understand ur answer can u please answer again
Step-by-step explanation:
(sec A+tan A)(1-sinA)
=(1/cos A + sin A/cos A)(1-sinA)
=[(1+sinA)/cosA](1-sinA)
=(1+sinA)(1-sinA)/cosA
=(1-sin^2 A)/cosA
=(cos^2 A)/cos A
=cos A
Hence proved
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