prove that=sin^2(a)+cos^2(a)=1
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Answered by
6
hay bro hear is ur answer :
let say a=x and b=y
picture helps,
draw a triangle on a plane, with angle theta, with hypotenuse c (let's say c=r)
x (adjacent side) over r will be cos(theta)
as well as y(opposite side of theta) over r will be sin(theta)
therefore, x^2 + y^2 = r^2
if you divide both sides by r^2 you have x^2/r^2 +y^2/r^2 = 1
since x^2/r^2 = cos^theta, and y^2/r^2=sin^2theta then
x^2/r^2 +y^2/r^2 = 1 will be cos^2theta +sin^theta = 1
____swarnim ___###
let say a=x and b=y
picture helps,
draw a triangle on a plane, with angle theta, with hypotenuse c (let's say c=r)
x (adjacent side) over r will be cos(theta)
as well as y(opposite side of theta) over r will be sin(theta)
therefore, x^2 + y^2 = r^2
if you divide both sides by r^2 you have x^2/r^2 +y^2/r^2 = 1
since x^2/r^2 = cos^theta, and y^2/r^2=sin^2theta then
x^2/r^2 +y^2/r^2 = 1 will be cos^2theta +sin^theta = 1
____swarnim ___###
simasima14:
thanks
Answered by
9
Hope that the pic is clear.....
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