prove that sin(270+theta)=(-cos theta)....
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sin(180+90+ theta)
sin[180+(90+theta)]
we know sin(180+theta)= -sin(theta)
so here - sin (90+ theta)
again we know sin(90+ theta)= cos( theta)
so we have -sin (90+theta)= - cos( theta)
sin[180+(90+theta)]
we know sin(180+theta)= -sin(theta)
so here - sin (90+ theta)
again we know sin(90+ theta)= cos( theta)
so we have -sin (90+theta)= - cos( theta)
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archinichi:
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Answer:
Analytically, go like this :
sin(270-x) = sin(180+(90-x)),
We know sin(180+k) = -sin(k)
Here, k = (90-x),
sin(180+k) = -sin(90-x) = -cosx
Graphically,
Draw a circle of unit radius, suppose x be any angle say 30°.
Plot 30° & 270–30=240° on the circle.
cos30° will lie on x-axis & sin240° will also lie on x-axis. They will be same in magnitude but if considering sign convention, they'll lie on the opposite side of the y-axis. This makes one positive and the other negative.
Proved!
Hope this will help
Step-by-step explanation:
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