Prove that
(sin^4A+cos^4A)/1-2sin^2Acos^2Q=1
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Open the identity (sin²A+cos²A)²
as (a+b)²=a²+b²+2ab
(sin²A+cos²A)²=sin^4A+cos^4A+2sin²Acos²A use sin²a+cos²a=1
(1)² - 2sin²Acos²A = sin^4A+cos^4A
1-2sin²Acos²A = sin^4A+cos^4A
hence proved
Hope that this answer will help you
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