Question

Prove that- sin(90°- A)cos (90°- A) = tanA/1+ cot^2(90-A)​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

We have ,

LHS = sin(90-A)cos(90-A)= cosA•SinA .

and ,

RHS = tanA/(1+cot^2A)= tanA/sec^2A = (sinA/cosA)cos^2A = sinA•cosA

Hence , LHS= RHS