Prove that sin A + cos'A=1.
Answers
Answered by
1
Answer:
ANSWER
sinA+cosA−1
sinA−cosA+1
=
sinA−(1−cosA)
sinA+(1−cosA)
=
2sin
2
A
cos
2
A
−2sin
2
2
A
2sin
2
A
cos
2
A
+2sin
2
2
A
=
cos
2
A
−sin
2
A
cos
2
A
+sin
2
A
=
cot
2
A
+1
cot
2
A
−1
=cot(
4
π
−
2
A
)
=
sin(
4
π
−
2
A
)×sin(
4
π
−
2
A
)
cos(
4
π
−
2
A
)×sin(
4
π
−
2
A
)
=
1−cos(
2
π
−A)
sin(
2
π
−A)
=
1−sinA
cosA
=
secA−tanA
1
Answered by
4
ᴛʜᴇʀᴇ ɪs ᴀɴ ᴇʀʀᴏʀ ɪɴ ᴛʜᴇ ǫᴜᴇsᴛɪᴏɴ
sɪɴᴀ + ᴄᴏsᴀ ≠ 1
ᴡᴇ ʜᴀᴠᴇ ᴀ ᴛʀɪɢɴᴏᴍᴇᴛʀɪᴄ ɪᴅᴇɴᴛɪᴛʏ,
ᴡʜɪᴄʜ ɪs,
sɪɴ²ᴀ + ᴄᴏs²ᴀ = 1
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