Prove that :
Sin²A-sin²B = Cos²B - COS²A
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Answer:
sin² A - sin² B = cos²B - cos² A
= 1 - sin² B -(1 - sin²A)
sin²A - sin²B = 1 - sin²B - 1 + sin²A
sin²A - sin²A - sin²B + sin²B -1+1
= 0
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