Math, asked by simranpkhrl, 9 months ago

Prove that :
Sin²A-sin²B = Cos²B - COS²A

Answers

Answered by Anonymous

0

Answer:

sin² A - sin² B = cos²B - cos² A

= 1 - sin² B -(1 - sin²A)

sin²A - sin²B = 1 - sin²B - 1 + sin²A

sin²A - sin²A - sin²B + sin²B -1+1

= 0

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