Prove that :- (sin@-cos@)^2=1-sin2@
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Hey there !!!!!!
~~~~~~~~~~~~~~~~~~~~~~~~~~~
Taking LHS
(sin@-cos@)²
using (a-b)² = a²-2ab+b²
=sin²@-2sin@cos@+cos²@
But sin²@+cos²@=1 and 2sin@cos@=sin2@
So,
=sin²@+cos²@-2sin@cos@
=1-sin2@
LHS=RHS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you............
~~~~~~~~~~~~~~~~~~~~~~~~~~~
Taking LHS
(sin@-cos@)²
using (a-b)² = a²-2ab+b²
=sin²@-2sin@cos@+cos²@
But sin²@+cos²@=1 and 2sin@cos@=sin2@
So,
=sin²@+cos²@-2sin@cos@
=1-sin2@
LHS=RHS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you............
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