Question

calculate the angular speed of the second's hand of a clock.If the length of the second's hand is 4cm calculate the speed (linear speed)of the tip of the hand.

Answer 1

A/Q :-
radius = 4cm =0.04 m
circumference = 2πr
=2×22/7×0.04
= 0.251m
= 0.25m (approximately)

time taken = 60 min. = 3600 second.
speed = distance / time
= 0.25/3600
=0.000069 m/s
=6.9 × 10^5 m/s

Answer 2

The speed of the tip of the hand is $4.18\times 10^3\ m/s$.

Explanation:

Given that,

The length of the second's hand is 4 cm or 0.04 m

To find,

Calculate the speed (linear speed)of the tip of the hand.

Solution,

The linear speed of the clock is given by :

$v=r\omega$

Where

$\omega=\dfrac{2\pi}{T}$ is the angular speed of the hand

$v=\dfrac{2\pi r}{T}$

T = 60 seconds

So, $v=\dfrac{2\pi \times 0.04}{60}$

$v=4.18\times 10^3\ m/s$

So, the speed of the tip of the hand is $4.18\times 10^3\ m/s$.

Learn more :

Angular speed

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