Math, asked by nikki2573, 7 months ago

prove that sum of 5 angles in a pentagon is 540 decrees

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Answered by Anonymous

Answer:

Triangle ABC= angle A+angle B+angle C=180. Similarly Triangles ACD & ADE are equal to 180. the sum of the three interior angles =180+180+180=540. hence the sum of the angles of a pentagon is 540.

Hope it helps you...

Answered by ashatalekar4

Answer:

sum of three interior angles 180 +180+180 =540

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prove that sum of 5 angles in a pentagon is 540 decrees​

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prove that sum of 5 angles in a pentagon is 540 decrees