prove that sum of any two sides of triangle is greater than the other side
Answers
Answered by
2
heya dear
here izz your answer
Given , AB ,BC,CA are the sides of the triangle ABC
To prove ;
- AB + BC > AC
AB + BC > AC
BC + AC > AB
construction : produce BA to D such that AD=AC join CD.
proof :- in triangle ACD , we have AC = AD
:- angle ACD = angle BDC
》 angle BCA + angle ACD > angle ADC
》angle BCD >angle BDC
》BD > BC
》BA + AD > BC
》 AB + AC > BC
HENCE PROVED
THANKS !!
here izz your answer
Given , AB ,BC,CA are the sides of the triangle ABC
To prove ;
- AB + BC > AC
AB + BC > AC
BC + AC > AB
construction : produce BA to D such that AD=AC join CD.
proof :- in triangle ACD , we have AC = AD
:- angle ACD = angle BDC
》 angle BCA + angle ACD > angle ADC
》angle BCD >angle BDC
》BD > BC
》BA + AD > BC
》 AB + AC > BC
HENCE PROVED
THANKS !!
Attachments:
Answered by
5
Hope this helps.....
Attachments:
Similar questions