Math, asked by TbiaSamishta, 1 year ago

Prove that tab2A+tan2B+tan2C=tan2A.tan2B.tan2C

Answers

Answered by aqibkincsem

8

"Its given that A + B + C= 180. Now, 2A + 2B +2C = 2*180 which can be written as 2a + 2b = 2pi-2c

tan(2a + 2b) = tan(2pi-2c)

(tan2a + tan2b)/( 1 - tan 2a tan2b) = -tan2c

tan2a + tan2b = -tan2c + tan2a tan2b tan2c

tan2a + tan2b + tan2c = tan2a tan2b tan2c"

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