Math, asked by apankaj, 1 year ago

prove that tan10°+tan35°+tan10°.tan35°=1

Answers

Answered by sarankumarmec

7

tan(A+B) = (tanA +tanB)/(1-tanAtanB)
tan45 = tan(10+35)
1 = (tan10+tan35)/(1-tan10tan35)
1-tan10tan35 = tan10+tan35
1 = tan10+tan35+tan10tan35

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