Question

prove that tan60-tan30/1+tan60×tan30=tan 30
please take photo of your answer

Answer 1

Hey frnd...

Thnx for asking this question.
Here is your answer...

♣ Trigonometry ♣
The solution is in the attachment.



Hope this would help you.

Answer 2

Answer:

Hence, the answer is =tan $30^o$.

Step-by-step explanation:

Step : 1  Given: tan30/1+tan60×tan30=tan 30

$\frac{\tan 60^{\circ}-\tan 30^{\circ}}{1+\tan 60^{\circ} \cdot \tan 30^{\circ}}$

$=\tan \left(60^{\circ}-30^{\circ}\right)$

$\left[\because \tan (A-B)=\frac{\tan A-\tan B}{1+\tan A \cdot \tan B}\right]$

$=\tan 30^{\circ}$

$=\frac{1}{\sqrt{3}}$

Hence, the answer is = tan $30^0 .$

Step : 2  Tan(/3) has a precise value of 1/3, or 1.7320508075 in decimal notation. It is the inverse of a 60-degree angle. The tangent of an angle of 60 degrees is about equivalent to 1.7321. 60 degrees is equal to 60° (180°) rad = /3 or 1.0471. Explanation: The angle 60° for tan 60 degrees is between 0° and 90°. (First Quadrant). Tan 60° value = 3 or 1.7320508 because the tangent function is positive in the first quadrant.

Step : 3 Since each of the angles of an equilateral triangle is 600 degrees, we can use this to get the value of tan 60 degrees mathematically. From A to BC, create a perpendicular line marked AD. The same method may be used to calculate additional tan degree values, such as 0°, 30°, 45°, 90°, 180°, 270°, and 360°.

To learn more about similar questions visit:

https://brainly.in/question/54085543?referrer=searchResults

https://brainly.in/question/19530490?referrer=searchResults

#SPJ3