Question

prove that
$\frac{ \sin(x + y) }{ \sin(x - y) } = \frac{ \tan(x) + \tan(y) }{ \tan(x) - \tan(y) }$

Answer 1

Please see the above attachment.

The identities of sine i.e,

sin(x+y) = sin x cos y+ cos x sin y

sin(x-y) = sin x cos y - cos x sin y
are used in it.


Hope it may help you

Answer 2

simple hope it helps you