Question

Prove that $\frac{(tan\theta + sec\theta - 1)}{(tan\theta - sec\theta + 1)}}$ = $\frac{1 + sin\theta}{cos\theta}}$

Answer 1

HELLO DEAR,



GIVEN:- (tanθ + secθ - 1)/(tanθ - secθ + 1)

=> {tanθ + secθ - (sec²θ - tan²θ)}/{tanθ - secθ + 1}

=> {(tanθ + secθ)(1 - secθ + tanθ)}/{tanθ - secθ + 1}

=> (tanθ + secθ)

=> (sinθ/cosθ + 1/cosθ)

=> (1 + sinθ)/cosθ



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