Prove that the area of a circular path of uniform
Answers
Answered by
3
width of the path = h
radius of inner circle = r
radius of outer circle= r + h
area of the path;
= area of outer circle - area of inner circle
= λ(r + h)² - λr²
= λ( r² + h² + 2λh) - λr²
= λ(h² + 2rh)
= λh(h+ 2r)
radius of inner circle = r
radius of outer circle= r + h
area of the path;
= area of outer circle - area of inner circle
= λ(r + h)² - λr²
= λ( r² + h² + 2λh) - λr²
= λ(h² + 2rh)
= λh(h+ 2r)
Answered by
0
Let h be the width of the path. And we will take r to be the radius of inner circle
The radius of the outer circle will be = (r+h)
The area of the path will be
= Area of outer circle – Area of inner circle
= π(r+h) square - πr square
= π (r square + h square + 2rh) - π r square
= π (h square + 2rh) = πh(h + 2r)
The radius of the outer circle will be = (r+h)
The area of the path will be
= Area of outer circle – Area of inner circle
= π(r+h) square - πr square
= π (r square + h square + 2rh) - π r square
= π (h square + 2rh) = πh(h + 2r)
Similar questions