Question

prove that the area of an equilateral triangle described on the sides of the square is equal to the half of the area of equilateral triangle described on one of its diagonal​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

1. Answer: Let the square be ABCD Let The triangle on the right side be BCF with BC as the base of the triangle and the side of the square BC. The triangle on the left be ACE with AC as diagonal of the square The sides of the  triangle BCF are a,a,a Take triangle ABC using pythgorus theorem AC =a√2 Then side AE=CE=a√2 Using area of a equilateral triangle  Area of triangle BCF =√3/4a Area of triangle AEC= √3/4(a√2)²                                   =√3/4×2a²                                    =√3/2a² Which is ½ area  of triangle AEC  Hence proved