Math, asked by ashanending, 2 months ago

prove that the diagonal of a parallelogram divides it into two congruent triangles

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Answered by Anonymous

7

Answer:

Statement : A diagonal of a parallelogram divides it into two congruent triangles.

Given : A parallelogram ABCD.

To prove : ΔBAC ≅ ΔDCA

Construction : Draw a diagonal AC.

Proof :

In ΔBAC and ΔDCA,

∠1 = ∠2 [alternate interior angles]

∠3 = ∠4 [alternate interior angles]

AC = AC [common]

ΔBAC ≅ ΔDCA [ASA]

Hence, it is proved.

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Answered by Astitva3591

3

Step-by-step explanation:

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