Question

prove that the intercept of a tangent between two parallel tangents to a circle substance a right angle at the centre​

Answer 1

$Hey Guys here is your answer$

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To prove:/BoD =90°

construction-OQ and OR

proof op l BD

Tengenent of any any point of a is circular perpendicular.......,..

∆S=OQB ~ OPB

similarly or ∆S / ORD and / OPD =/ 3+/ 4

So / 1=/ 2

/ BOD=/ 1+/ 3

=1/2(/ 1+/ 2+/ 3+/ 4)

=1/2 ×180°

=90°

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Answer 2

Answer:

PQ and RS are two parallel tangents to a circle with centre O. AB is tangents to a circle at C, intersecting PQ and RS at A and B respectively