prove that the line joining the midpoint of two equal chords of a circle subtends equal angles with the chord.
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In the question, they have given that the chords are equal.
Therefore, let the chords be AB and CD.(refer diagram)
Taking ΔABO and ΔCDO
AB=CD(Given)
OA=OC(Radii)
OB=OD(Radii)
∴ΔABO≅ΔCDO(SSS congruency)
∴∠AOB=∠COD (Corresponding parts of congruent triangles are equal)
Hence proved.
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