Prove that the line of centres of two intersecting circles subtends equal angles at the two point of intersection
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In ∆AOO′ and ∆BOO′, we have
AO = BO [Radii of the same circle]
AO′ = BO′ [Radii of the same circle]
OO′ = OO′ [Common]
∴ ∆AOO′ ≅ ∆BOO′ [SSS axiom]
⇒ ∠OAO′ = ∠OBO′ [CPCT]
Hence, the line of centres of two intersecting circles subtends equal angles at the two points of intersection
AO = BO [Radii of the same circle]
AO′ = BO′ [Radii of the same circle]
OO′ = OO′ [Common]
∴ ∆AOO′ ≅ ∆BOO′ [SSS axiom]
⇒ ∠OAO′ = ∠OBO′ [CPCT]
Hence, the line of centres of two intersecting circles subtends equal angles at the two points of intersection
Manish1933:
just a little mistake od must ob
i think it is correct
but u written od in place of ob
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Answer:
hi
this is ur answer
if u satisfy, then mark it as brainliest ♥️
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