Question

Prove that the lines 3x – 2y + 5 = 0 and 4x + 6y – 23 = 0 are perpendicular.​

Answer 1

Step-by-step explanation:

y=3/2x+5/2. .....(1)

slope m1 = 3/2

y=-2/3x +23/6. ......(2)

slope m2 =-2/3

m1xm2=-1. are condition of perpendicular lines

= 3/2x-2/3

= -1

hence proved