prove that the minimum value of x cube + 1 by x cube is greater than its maximum value
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x^3+1)/x^3=1+ 1/x^3
let y = 1+ 1/x^3
dy/dx=-3/x^4<0
for x=1 ,-1 but y=2,0
dy/dx= -3<0
-3<0<2
let y = 1+ 1/x^3
dy/dx=-3/x^4<0
for x=1 ,-1 but y=2,0
dy/dx= -3<0
-3<0<2
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