Question

Prove that the points (-2,1), (2,-2) and (5,2) are vertices of a right angled triangle

Answer 1

Let us take (- 2,1)as A
(2,-2)as B
And (5,2) as C

Now using distance formula
$\sqrt{ {(x2 - x1})^{2} + ({y2 - y1)}^{2} }$
Find length of AB, BC, AC
then
Using pythagoras theorem..

Hypotenuse square = base square + perpendicular square
Put the values of AB, BC, AC
in tje the pythagoras theorem
If left hand side comes equal to right hand side then.. The given triangle is right angled



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