prove that the sides opposite to equal angles of a triangle are equal
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Answered by
2
Answer:
Step-by-step explanation:
From the given information:
∠
B
A
C
=
∠
B
C
A
And:
A
B
=
B
C
To prove that
A
B
=
B
C
, we will need to construct an angle bisector
B
D
to
∠
A
B
C
. Thus:
∠
A
B
D
=
∠
C
B
D
by construction.
We have two triangles,
△
A
B
D
and
△
C
B
D
. For the two triangles, the side
B
D
is common.
Therefore, using the AAS postulate for congruence, we can say that
△
A
B
D
≅
△
B
C
D
since
∠
B
A
C
≅
∠
B
C
A
,
∠
A
B
D
≅
∠
C
B
D
and
B
D
≅
B
D
.
Therefore, by the corresponding sides of congruent triangles, we can as well conclude that
B
A
=
B
C
Answered by
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Step-by-step explanation:
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