Question

prove that the sides with measures 10cm, 8cm and 6cm are the sides of a right angled triangle.​

Answer 1

Answer:

yes it's a sides of right angled triangle

Step-by-step explanation:

${10}^{2} = {8}^{2} + {6}^{2} \\ 100 = 64 + 36 \\ 100 = 100$

it satisfies the Pythagoras theorem

$hypotenuse^{2} = \: sum \: of \: square \: of \: other \: two \: sides$

therefore it is a sides of right angled triangle