Prove that two angles in the same segment of a circle are equal.
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Let AB be the arc of the minor segment of a circle with center O. Let C and D be points on the major segment of the circle.
Angles ∠ACB = 1/2 * ∠AOB (angle made at the center by arc AB)
angle ∠ADB = 1/2 * ∠AOB.
Hence, ∠ACB = ∠ADB
Angles ∠ACB = 1/2 * ∠AOB (angle made at the center by arc AB)
angle ∠ADB = 1/2 * ∠AOB.
Hence, ∠ACB = ∠ADB
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