Math, asked by yashudaisandhu, 10 months ago

prove that underroot 5 is an irrational number (without supposition)

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Answered by Mrinalkoshal
1

Answer:

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Answered by shraddhazutshi312
0

as √5=2.2360 bar (approx)

so it is non terminating and non repeating

as we know that irrational numbers have non terminating and non repeating so it is a irrational no.

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