prove that X square + 6 X + 15 has no zero
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Discriminant = b² - 4ac
Here,
a = 1
b = 6
c = 15
Discriminant = b² - 4ac
=> (6)² - 4(1×15)
=> 36 - 60
=> -24
As - 24<0 ,the given equation does not any real root.
Here,
a = 1
b = 6
c = 15
Discriminant = b² - 4ac
=> (6)² - 4(1×15)
=> 36 - 60
=> -24
As - 24<0 ,the given equation does not any real root.
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