Question

prove the following identity:
[1 + cot (theta) + tan (theta)] [sin (theta) - cos (theta) = sec(theta) by cosec^2(theta) - cosec(theta) by sec^2(theta)
${( 1 + \cot(theta) + \tan(theta)) } ( { \sin(theta) - \cos(theta)) } = \frac{ \sec(theta) }{ { \cosec}^{2}(theta)}- \frac{ \cosec(theta) }{ { \sec }^{2}(theta)}$
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Answer 1

Answer:

hope it will help you and mark as Brainliest

Answer 2

sorry i dont know your amswer but i mark your one answer exellent and thanks to that answer