prove the following identity.
sin^4theta-cos^4theta=1-2cos^2theta
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Answer:
To Prove:sin⁴x - cos⁴x = 1- 2sin²x.cos²x
Step-by-step explanation:
Solving LHS:
= (sin²x-cos²x)² [ (a-b)²=a²+b²-2ab]
= sin⁴x + cos⁴x - 2sin²x.cos²x [sin²x+cos²x = 1]
= 1- 2sin²x.cos²x
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