Prove the following trigonometric identities:
tanA+tanB/cotA+cotB=tanAtanB
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ya it's very easy question
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tanA+tanB / cotA+cotB = tanA tanB proved
Step-by-step explanation:
To prove: tanA+tanB / cotA+cotB = tanA tanB
Proof:
LHS = tanA+tanB / cotA+cotB
= (SinA/CosA + SinB/CosB) / (CosA/SinA + CosB/SinB)
= [(SinA.CosB + SinB.CosA) / CosA.CosB] / [(SinB.CosA +SinA.CosB) / SinA.SinB]
= SinA.SinB / CosA.CosB
= TanA.TanB
= RHS
RHS = LHS
Hence proved.
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