Prove the following trigonometric identities:
tan²Asec²B-sec²Atan²B=tan²A-tan²B
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tan²A sec²B -sec²A tan²B = tan²A - tan²B proved
Step-by-step explanation:
To prove: tan²A sec²B -sec²A tan²B = tan²A - tan²B
Proof:
LHS = tan²A sec²B - sec²A tan²B
= tan²A (1 + tan²B) - ( 1 + tan²A). tan²B
= tan²A + tan²A. tan²B - tan²B - tan²A. tan²B
=tan²A - tan²B
= RHS
RHS = LHS
Hence proved.
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