prove the identities:- tanA/1+tanA2=sinA×CosA
Answers
Answered by
5
Step-by-step explanation:
see your answer here
and
mark as brilliant
Attachments:
Answered by
5
tanA/1+tan^2A=sinA×cosA
(sinA/cosA) /1+(sin^2A/cos^2A)=sinA×cosA
(sinA/cosA)/(cos^2A+sin^2A/cos^2A)=sinA×cosA
sinA/cosA ×cos^2A/1 =sinA×cosA(sin^2A+cos^2=1
=sinA×cosA = sinA×cosA
Similar questions