Math, asked by Sharon15, 1 year ago

Prove the identity cos^4 A - cos^2 A = sin^4 A - sin^2 A

Answers

Answered by guptaramanand68
4

 \cos ^{4} (x)  -  \cos ^{2} (x)  \\  =  (\cos ^{2} (x) )^{2}  -  \cos ^{2}(x)  \\  = (1 -  \sin^{2} (x)) ^{2}   - (1 -  \sin ^{2} (x) ) \\ =  1 - 2 \sin ^{2} (x)  +  \sin ^{4} (x)  - 1 +  \sin ^{2} (x)  \\  =   \boxed{\sin ^{4} (x)  -  \sin ^{2} (x)}

Sharon15: thnx
Sharon15: Can explain it step by step.... Plz
guptaramanand68: I used two identites (a-b)^2 = a^2 - 2ab +b^2 and (sinx)^2+(cosx)^2=1
Sharon15: Oh!!!! ......thnx
guptaramanand68: You're welcome.
Answered by shiriprasadneelam
1
Here is your answer with explanation
Attachments:

Sharon15: Thnx
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