Prove the identity:
secθ + cosecθ x cotθ = secθ x (cosecθ)^2
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Answer:
Now,
(cosecθ−sinθ)(secθ−cosθ)
=(sinθ1−sinθ)(cosθ1−cosθ)
=(sinθ1−sin2θ)(cosθ1−cos2θ)
=sinθcosθcos2θsin2θ=sinθcosθ (1)
Next, consider tanθ+cotθ1
=cosθsinθ+sinθcosθ1
=(sinθcosθsin2θ+cos2θ)1
=sinθcosθ (2)
From (1) and (2), we get
(cosecθ−sinθ)(secθ−cosθ)=tanθ+cotθ
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