Math, asked by afrinalam2003, 9 months ago

Prove the the answer 1+1=2(of class12)​

Answers

Answered by likithareddy1
0

Answer:

☝️+☝️=✌

Step-by-step explanation:

if it is correct mark me as brainlist

Answered by sanishaji30
2

Answer:

Math 214 - Addition, Subtraction, Multiplication and Division.  First mathematical proof class in College, sophomore year.

I remember this too clearly as it took me 5 hours to figure but once I did it was all too easy.

This is quite easy and have infinite ways to prove, but this is the way we used.  It is ALL in the definition of 1, 2 and +.  I am going to shorten it to save some time and make it easily understandable.

Let N be the entire set of natural numbers {1, 2, 3, 4....}, let count x be 1 then 2 then 3 then 4 then...then x.  Let n be a list of natural numbers.  Let H(n) be {x1} if n = {x1, x2, x3...xn} or, the head of the element in the list, Let T(n) be {x2, x3, x4...xn} or the tail of the list.  Let C(x) be T(N) recursively count x-1, or T(N) = {1,2,3,4...} once, T({1,2,3,4...} = {2,3,4,5...} twice, T({2,3,4,5...} = {3,4,5,6..} three times...x times.

Now let x + y be: C(x) = n, count y of H(T(n)) recursively i.e. H(T(n)) becomes n in the subsequent iterations.

So 1 + 1: C(1), count 1 of H (T(n)).  C(1) means count N to 1, then you are left with the tail of N once so (1,2,3,4,5...}, now this is set to n (just a list of natural numbers.  Now take this n and plug it into H(T(n) which gives you first T{1,2,3...} = {2,3,4...} and then H{2,3,4...} = {2}.

So by definition of 1 + 1, we get {2} or 2.

The idea is you can define x + y where x is the starting point of the list of natural numbers so if x is 5, then start the list with 5 i.e. {5,6,7,8...}.  y is the number of iterations you want to take 1 step "forward" so if y is 3, then you start with 5, take 1 step forward 3 times gives you 8.  

You'll have to define what is forward, what is taking a step forward, what is the start point and how do you get there, what is left when you get to the starting point (the rest of the natural numbers including the starting point itself is needed), what is counting (you need to iterate y times so you need to count.  Then you can prove x + y = whatever.   Obviously it takes a lot of work because you can't just tell people look at this list, and move one number to the right and have this accepted as a mathematical proof.

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