Question

prove this please guys help.

Answer 1

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Answer 2

[tan(x) /sekant(x-1)]^2=2* kosekant(x)...2*csc(x)...=2/sine(x)

sekant=1/kosine, so 1/sekant=kosine

tan=sine/kosine, so tan*kosine=(sine/kosine)*kosine=sine

but yu hav tan(x)*kosine(x-1)
hope it helps