prove this please guys help.
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[tan(x) /sekant(x-1)]^2=2* kosekant(x)...2*csc(x)...=2/sine(x)
sekant=1/kosine, so 1/sekant=kosine
tan=sine/kosine, so tan*kosine=(sine/kosine)*kosine=sine
but yu hav tan(x)*kosine(x-1)
hope it helps
sekant=1/kosine, so 1/sekant=kosine
tan=sine/kosine, so tan*kosine=(sine/kosine)*kosine=sine
but yu hav tan(x)*kosine(x-1)
hope it helps
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