Question

proved this tanA. tanB. tanC = tanA+tanB+tanC

Answer 1

heya friend !!!.........bro

.it's easy bhai
______________
As you know the sum of all angle of a triangle is 180°

so <A+<B+<C=180°
=><A+<B=180°-<C
=>tan(A+B)=tan180°-<C)
=>tanA+tanB/1-tanA*tanB=-tanC
=>tanA+tanB=-tanC+tanA*tanB*tanC
=>tanA+tanB+tanC=tanA*tanB*tanC...

lhs =Rhs. ..

here prooved ......

hope it help you..bhai ......

@Rajukumar1☺☺