pt is a tangent and pAB is a secent if pt = 6cm and AB=5cm <br />then find the length of PA <br />this question is very important for board exam class 10 plz solve the question
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By tangent secant property
➡PA×PB=PT^2
➡PA×(PA+AB)=36
➡PA×(PA+5)=36
➡PA^2+5PA-36=0
➡PA^2+9PA-4PA-36=0
➡PA(PA+9)-4(PA+9)=0
➡(PA-4)(PA+9)
Either PA=4 or PA=-9
But PA can't be negative as it is a side therefore we discard PA=-9
Hence,PA=4CM
➡PA×PB=PT^2
➡PA×(PA+AB)=36
➡PA×(PA+5)=36
➡PA^2+5PA-36=0
➡PA^2+9PA-4PA-36=0
➡PA(PA+9)-4(PA+9)=0
➡(PA-4)(PA+9)
Either PA=4 or PA=-9
But PA can't be negative as it is a side therefore we discard PA=-9
Hence,PA=4CM
yash510:
but ur answer wrong
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