PX equals to 6 x squared minus 3 minus 7 x
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P(x) = 6x^2 - 7x - 3
To find zeros let P(x) = 0
So, 6x^2 - 7x - 3 = 0
6x^2 - 9x + 2x - 3 = 0
3x (2x - 3) + 1 (2x - 3) = 0
(2x - 3) (3x + 1) = 0
=> x = 3/2 & x = - 1/3
Hope this answer will help u...
To find zeros let P(x) = 0
So, 6x^2 - 7x - 3 = 0
6x^2 - 9x + 2x - 3 = 0
3x (2x - 3) + 1 (2x - 3) = 0
(2x - 3) (3x + 1) = 0
=> x = 3/2 & x = - 1/3
Hope this answer will help u...
saaniya30:
have to find the zeros
welcome
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