Question

python program to find whether the number is prime or not............



don't dare to spam✔✔✔​

Answer 1

Answer:

Python program to check whether a number is Prime or not

Given a positive integer N. The task is to write a Python program to check if the number is prime or not.

Definition: A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. The first few prime numbers are {2, 3, 5, 7, 11, ….}.Input: n = 11

Output: true

Input: n = 15

Output: false

Input: n = 1

Output: false

The idea to solve this problem is to iterate through all the numbers starting from 2 to (N/2) using a for loop and for every number check if it divides N. If we find any number that divides, we return false. If we did not find any number between 2 and N/2 which divides N then it means that N is prime and we will return True.

Below is the Python program to check if a number is prime:

# Python program to check if

# given number is prime or not

num = 11

# If given number is greater than 1

if num > 1:

# Iterate from 2 to n / 2

for i in range(2, num//2):

# If num is divisible by any number between

# 2 and n / 2, it is not prime

if (num % i) == 0:

print(num, "is not a prime number")

break

else:

print(num, "is a prime number")

else:

print(num, "is not a prime number")

Output:

11 is a prime number

Optimized Method

We can do following optimizations:

Instead of checking till n, we can check till √n because a larger factor of n must be a multiple of smaller factor that has been already checked.

The algorithm can be improved further by observing that all primes are of the form 6k ± 1, with the exception of 2 and 3. This is because all integers can be expressed as (6k + i) for some integer k and for i = ?1, 0, 1, 2, 3, or 4; 2 divides (6k + 0), (6k + 2), (6k + 4); and 3 divides (6k + 3). So a more efficient method is to test if n is divisible by 2 or 3, then to check through all the numbers of form 6k ± 1. (Source: wikipedia)

# A optimized school method based

# Python3 program to check

# if a number is prime

def isPrime(n) :

# Corner cases

if (n <= 1) :

return False

if (n <= 3) :

return True

# This is checked so that we can skip

# middle five numbers in below loop

if (n % 2 == 0 or n % 3 == 0) :

return False

i = 5

while(i * i <= n) :

if (n % i == 0 or n % (i + 2) == 0) :

return False

i = i + 6

return True

# Driver Program

if (isPrime(11)) :

print(" true")

else :

print(" false")

if(isPrime(15)) :

print(" true")

else :

Examples :