Question

Q, 1)factorie y3+1/8y3​

Answer 1

Answer:

We know the identity a

3

−b

3

=(a−b)(a

2

+b

2

+ab)

Using the above identity, the equation 8y

3

−1 can be factorised as follows:

8y

3

−1=(2y)

3

−(1)

3

=(2y−1)[(2y)

2

+1

2

+(2y×1)]=(2y−1)(4y

2

+1+2y)

Hence, 8y

3

−1=(2y−1)(4y

2

+1+2y)